Slide Simulation

http://phet.colorado.edu/en/simulation/wave-interference

• Distance of wavelengths dots are dependent on the distance of the lens from wall.  (our  measurements are from 1,250mm away from wall)
• Distance of dots are not dependent on distance of laser.
• Dots are bigger and brighter (more intense) at the center and fade as they travel away from the center.

(Quad II) = A vertical line of dots spaced...
Green=10 mm apart
Red = 14 mm apart
Pattern printed on the slide? 2 slit
Distance between slits on slide: 1392.28nm

(Quad I) = A vertical line of dots spaced...
Green =  7mm apart.
Red = 9mm apart
Pattern printed on the slide? 2 slits
Distance between slits on slide: 7mm/

(Quad IV) =A horizontal line of dots spaced...

Green =  7mm apart.
Red = 9mm apart
Pattern printed on the slide? 2 slits
Distance between slits on slide: 7mm

(Quad III) = A horizontal line of dots spaced...
Green= 10mm apart. 
Red = 14mm apart.
Pattern printed on the slide? 2 slits
Distance between slits on slide: 1392.28nm

slits seperation: closer = dots spread out.
slits seperation: further apart = dots closer together.

1. What is the 4 patterns printed on the slides? Somehow draw and post this pattern on your blog, and explain how you arrived at this pattern.

a & c produce the horizontal of dots.  b & d produce the vertical dots.

We experimented on the wave simulater and found a similiar pattern to ours.

2. Determine the distance between the line patterns on the slides, and how thick the lines may be based on your changing of the simulator to duplicate the pattern you measured.
Distance betwen the line patterns on the slide:  smaller slit width = more dots
Thickness of lines:   smaller slit seperation = less dots

Due to the limitations of the simulation tool, we were unable give you an accurate picture of the simulation.  Our ratio in real life was 125%. (x=1250mm,Y=10mm)  The biggest I could represent on the simulator was 7%.  Math calculations tell us that the slit width is 22nm (x=174035 nm, Y=1392.28 nm)  theta = .458356468 degrees 

3. Setup the light wave simulator to simulate the patterns on the 35 mm slides. Grab a picture of these simulations and post them for each of your patterns.

4. Which light can measure smaller things, red light or green light? Post an image of the simulator demonstrating this.
The green light can measure smaller things b/c it has shorter wavelengths. (like blue-ray= smaller burns marks for more laser)

Blog Post 6: Good Nano Websites

Develop a list of at least 10 good Nano websites. Get two types, one of a general nature, and one that is focused on your interests.

General
1.  Nanowerk.com
2.  Nanotech-now.com
3.  Azonano.com
4.  http://nanotechweb.org/cws/channel/multimedia
5.  http://www.nano.org.uk/nanotechnology-images
Focused Interest
6.  http://penmedia.org/video/maynard.html
7.  http://www.howstuffworks.com/nanotechnology.htm
8.  http://www.nano-tex.com/technologies/aquapel.html
9.  http://plus.maths.org/content/os/latestnews/may-aug10/nano/index
10.http://www.zyvex.com/nano/


http://nano.gov/
http://nanohub.org/about/contact

Blog Post 5: Wave Interference Simulation Activities

Blog Post 5

1. Measure the wavelength of two drops of different amplitude, leave frequency constant.
Amplitude = 1.34 cm Wavelength = 5.12 cm
Amplitude = .18 cm Wavelength = 5.12 cm

2. Measure the wavelength of two drops with different frequency, leave amplitude constant.

Frequency = 1.36cm apart Wavelength = 1.26 cm
Frequency = 1.98cm apart Wavelength = 1.98 cm

3. Explain your results for Question 1 and 2.

+/- Amplitude = same wavelength
+ Frequency = Shorter Wavelength / - Frequency = Longer Wavelength

4. Introduce a second faucet for the next set of questions.

- measure the wavelength of the two drips, in cm

x= 2.33cm

y= 2.33 cm

- then measure distances from each drip to the 6 constructive interference points and report these values, cm

x to 1= 2.96cm          y to 1= 2.96cm

x to 2= 2.96cm          y to 2 = 5.17cm

x to 3= 5.17cm          y to 3 = 2.96cm

x to 4= 7.28cm          y to 4 = 7.28cm

x to 5= 5.17cm          y to 5 = 5.17cm

x to 6= 7.28cm          y to 6 = 5.17cm

- explain the observation you have on the distance comparisons to the constructive interference points to the wavelength of the water wave.

Creates a PATTERN (of distance): 

 x/y to 1 & 5 = same distance  ,  x/y to 2 & 3 = same-opposite  ,    x/y to  4 & 6 = same-opposite
= Waves meet up at the same pattern.  Constructive (full waves) and Destructive (half waves) patterns. The dots meet at full wavelengths + their multiples.

Blogpost 4: Wave Interference

Make sure that the following simulation runs for next week. Play with the simulation and get a sense of what it is showing.

http://phet.colorado.edu/en/simulation/wave-interference

Blog Post 3: Waves

Simulations

Questions:

1. which takes more energy, slow up and down, or fast up and down?

Fast up and down uses more energy/calories

2. fast frequency corresponds to low energy or high energy?

High energy

3. Determine the frequency of the provided wave(frequency 27, amplitude 50)in Hz?

1.2 Hz        (:83 sec/cycle )

4. Determine the frequency of the provided wave(frequency 100, amplitude 50) in Hz?

1.8 Hz        (:55 sec/cycle)

5. Determine the frequency of the provided wave(frequency 27and amplitude 100) in Hz.

1.25 Hz       (:80 sec/cycle)

6. What is the wavelength of the provided wave(frequency 27, amplitude 50)in cm?

50 cm

7. What is the wavelength of the provided wave(frequency 100, amplitude 50)in cm?
33cm

8. Describe the relationships between energy, frequency and wavelength. Include descriptions for relationships of all three.
Frequency, not amplitude, determines energy.     (Energy and Amplitude are not related.)

Energy is directly proportional to frequency. 

Energy inversely proportional to wavelength.

 (More energy/frequency= shorter wavelength. 

   lower energy/frequency= longer wavelength)

NaCl Lab 9/20/11

1)  Post an image of your unit cell model on your blog.

2)  a.)Determine and post the mass of one cube of NaCl. b) Calculate and post the number of moles of NaCl in one cube. c)Calculate and post the number of NaCl molecules in one cube of salt.

 a) Molar mass (molecular weight) of one unit cell of  NaCl =  233.77 g/mole
    
Work:
    Mass Cl       = 35.4527
 + Mass Na      = 22.9898
NaCl Molecule   58.443 grams/mole  * 4 = 233.77 grams/mole  in a NaCl Unit Cell

b)  # of moles of NaCl in one unit cell =  1.459238452 E^ -22 grams

Work:
        233.77 grams         =1.459238452 E -22 grams
6.02 x 10^23 atoms

c)  # of molecules in one unit cell of salt =  4

3) a) Determine the dimension of one cube of salt.  b) Based on the dimensions determined by the unit cell model, determine and post the number of NaCl in one cube of salt.

a)  one cube of salt = .7mm

b) 5.49153314 E 16nm NaCl in one salt cube.

Here is our work:
 [.543 nm in a unit cell,  1,000,000nm=1m,  543,000 nm in a 1mm cube of salt.  Our cube of salt is .77mm.  Therefore, .543nm * .7mm = 380,100 nm. We now have to cube it (^3)  to get the volume... 380,100^3= 5.49153314 E 16nm in one salt cube]

Blog Post 1: Describe 10nm and mole of atoms

A MOLE of Atoms=
  -  6.02 X 10^23 carbon atoms.
  -  15 trillion earths
  -  The quantity of anything.  Any time you want to refer to a large number of things.  It's easier to say the unit "mole", than to write 6.02 x 10^23.
  -  Gives us a consistent method to convert between atoms/ molecules and grams. 
  -  Although it doesn't seem like it at first, once one becomes familiar with a mole, it will be as normal as a dozen or a byte.
  -  If you had a mole of pennies, you could give out enough money to everyone in the world so that they could spend a million dollars every hour, day and night, for the rest of their lives.
  -  If you had exactly one mole of sheets of paper, you could make one million equal stacks from sea level on the earth that would pass the sun.
  -  Given that the volume of a grain of sand is approximately 10^-12 m³, and given that the area of the United States is about 10¹³m², it therefore follows that a mole of sand grains would cover the United States in approximately one centimeter of sand.

10 NANOMETERS =
  - 1nm=10^ -9m    (reduced 1 billion meters)
  - 10nm= 10^ -8m (.000000001)
  - 100nm= 10^ -7m
  - 1,000nm= 10^ -6m     = 1mm

  -  size of a virus
  -  Size of a cell wall
  -  as a mm is to a km a nm is to a m
  -  10 nm = 10 nanometres = 10⁻⁸ metres
  -  10 nm — lower size of tobacco smoke